What are the solutions to the equation 2x^2+16x-10=0 ?

The solutions to the equation 2x^2+16x-10=0 are x=-4+sqrt(21),x=-4-sqrt(21)

Find the zeros of 2x^2+16x-10=0

The zeros of 2x^2+16x-10=0 are x=-4+sqrt(21),x=-4-sqrt(21)

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2 x^{2} + 16 x - 10 = 0

x = - 4 + 21, x = - 4 - 21

Decimal Notation

x = 0.58257 \dots, x = - 8.58257 \dots

Solution steps

2 x^{2} + 16 x - 10 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- 16 \pm 1 6 ^{2} - 4 \cdot 2 ( - 10 )}{2 \cdot 2}

1 6^{2} - 4 \cdot 2 (- 10) = 421

x_{1, 2} = \frac{- 16 \pm 4 21}{2 \cdot 2}

Separate the solutions

x_{1} = \frac{- 16 + 4 21}{2 \cdot 2}, x_{2} = \frac{- 16 - 4 21}{2 \cdot 2}

x = \frac{- 16 + 4 21}{2 \cdot 2} : - 4 + 21

x = \frac{- 16 - 4 21}{2 \cdot 2} : - 4 - 21

The solutions to the quadratic equation are:

x = - 4 + 21, x = - 4 - 21

6 x^{2} - 5 x = 0

6363

(\frac{\frac{1}{4}}{2})^{2}

22

- 0.5 m - 0.75 = 2.15

What are the solutions to the equation 2x^2+16x-10=0 ?
The solutions to the equation 2x^2+16x-10=0 are x=-4+sqrt(21),x=-4-sqrt(21)
Find the zeros of 2x^2+16x-10=0
The zeros of 2x^2+16x-10=0 are x=-4+sqrt(21),x=-4-sqrt(21)