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受欢迎的代数 >

solvefor x,CT(x)=x^2-50x-10

解答

求解

x, CT (x) = x^{2} - 50 x - 10

解答

x = \frac{50 + TC + T ^{2} C ^{2} + 100 TC + 2540}{2}, x = \frac{50 + TC - T ^{2} C ^{2} + 100 TC + 2540}{2}

求解步骤

CT (x) = x^{2} - 50 x - 10

整理后得

x TC = x^{2} - 50 x - 10

交换两边

x^{2} - 50 x - 10 = x TC

将

x TC

para o lado esquerdo

x^{2} - 50 x - 10 - x TC = 0

改写成标准形式

a x^{2} + b x + c = 0

x^{2} - (50 + TC) x - 10 = 0

使用求根公式求解

x_{1, 2} = \frac{- ( - 50 - TC ) \pm ( - 50 - TC ) ^{2} - 4 \cdot 1 \cdot ( - 10 )}{2 \cdot 1}

化简

(- 50 - TC)^{2} - 4 \cdot 1 \cdot (- 10) : T^{2} C^{2} + 100 TC + 2540

x_{1, 2} = \frac{- ( - 50 - TC ) \pm T ^{2} C ^{2} + 100 TC + 2540}{2 \cdot 1}

将解分隔开

x_{1} = \frac{- ( - 50 - TC ) + T ^{2} C ^{2} + 100 TC + 2540}{2 \cdot 1}, x_{2} = \frac{- ( - 50 - TC ) - T ^{2} C ^{2} + 100 TC + 2540}{2 \cdot 1}

x = \frac{- ( - 50 - TC ) + T ^{2} C ^{2} + 100 TC + 2540}{2 \cdot 1} : \frac{50 + TC + T ^{2} C ^{2} + 100 TC + 2540}{2}

x = \frac{- ( - 50 - TC ) - T ^{2} C ^{2} + 100 TC + 2540}{2 \cdot 1} : \frac{50 + TC - T ^{2} C ^{2} + 100 TC + 2540}{2}

二次方程组的解是:

x = \frac{50 + TC + T ^{2} C ^{2} + 100 TC + 2540}{2}, x = \frac{50 + TC - T ^{2} C ^{2} + 100 TC + 2540}{2}

作图

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