zs

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

受欢迎的代数 >

0=40+5t-5t^2

解答

0 = 40 + 5 \cdot t - 5 \cdot t^{2}

解答

t = - \frac{- 1 + 33}{2}, t = \frac{1 + 33}{2}

+1

十进制

t = - 2.37228 \dots, t = 3.37228 \dots

求解步骤

0 = 40 + 5 t - 5 t^{2}

交换两边

40 + 5 t - 5 t^{2} = 0

改写成标准形式

a x^{2} + b x + c = 0

- 5 t^{2} + 5 t + 40 = 0

使用求根公式求解

t_{1, 2} = \frac{- 5 \pm 5 ^{2} - 4 ( - 5 ) \cdot 40}{2 ( - 5 )}

5^{2} - 4 (- 5) \cdot 40 = 533

t_{1, 2} = \frac{- 5 \pm 5 33}{2 ( - 5 )}

将解分隔开

t_{1} = \frac{- 5 + 5 33}{2 ( - 5 )}, t_{2} = \frac{- 5 - 5 33}{2 ( - 5 )}

t = \frac{- 5 + 5 33}{2 ( - 5 )} : - \frac{- 1 + 33}{2}

t = \frac{- 5 - 5 33}{2 ( - 5 )} : \frac{1 + 33}{2}

二次方程组的解是:

t = - \frac{- 1 + 33}{2}, t = \frac{1 + 33}{2}

作图

流行的例子

p^{2} + 10 \cdot 10 = 4160

4 X^{2} - 32 X + 20 = 0

14 x^{2} - 45 x - 14 = 0

- 4 x^{2} - 24 x - 28 = 0

12 x^{2} - 7 x - 1 = 0