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人気のある代数 >

solvefor x,f(x+1)=2x^2+8

解

解く

x, f (x + 1) = 2 x^{2} + 8

解

x = \frac{f + f ^{2} - 8 ( 8 - f )}{4}, x = \frac{f - f ^{2} - 8 ( 8 - f )}{4}

解答ステップ

f (x + 1) = 2 x^{2} + 8

拡張

f (x + 1) : x f + f

x f + f = 2 x^{2} + 8

辺を交換する

2 x^{2} + 8 = x f + f

f

を左側に移動します

2 x^{2} + 8 - f = x f

x f

を左側に移動します

2 x^{2} + 8 - f - x f = 0

標準的な形式で書く

a x^{2} + b x + c = 0

2 x^{2} - f x + 8 - f = 0

解くとthe二次式

x_{1, 2} = \frac{- ( - f ) \pm ( - f ) ^{2} - 4 \cdot 2 ( 8 - f )}{2 \cdot 2}

簡素化

(- f)^{2} - 4 \cdot 2 (8 - f) : f^{2} - 8 (8 - f)

x_{1, 2} = \frac{- ( - f ) \pm f ^{2} - 8 ( 8 - f )}{2 \cdot 2}

解を分離する

x_{1} = \frac{- ( - f ) + f ^{2} - 8 ( 8 - f )}{2 \cdot 2}, x_{2} = \frac{- ( - f ) - f ^{2} - 8 ( 8 - f )}{2 \cdot 2}

x = \frac{- ( - f ) + f ^{2} - 8 ( 8 - f )}{2 \cdot 2} : \frac{f + f ^{2} - 8 ( 8 - f )}{4}

x = \frac{- ( - f ) - f ^{2} - 8 ( 8 - f )}{2 \cdot 2} : \frac{f - f ^{2} - 8 ( 8 - f )}{4}

二次equationの解:

x = \frac{f + f ^{2} - 8 ( 8 - f )}{4}, x = \frac{f - f ^{2} - 8 ( 8 - f )}{4}

グラフ

人気の例

x^{2} - 18 x + 42 = 0

r^{2} = 81

completesquare 9x^2-6x

co m pl e t es q u a re 9 x^{2} - 6 x

3 y (y) = x^{2} + 12

(4x-3)^2+(4x+3)^2=25

(4 x - 3)^{2} + (4 x + 3)^{2} = 25