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受欢迎的代数 >

solvefor a,a^2-a+bc=0

解答

求解

a, a^{2} - a + b c = 0

解答

a = \frac{1 + 1 - 4 b c}{2}, a = \frac{1 - 1 - 4 b c}{2}

求解步骤

a^{2} - a + b c = 0

使用求根公式求解

a_{1, 2} = \frac{- ( - 1 ) \pm ( - 1 ) ^{2} - 4 \cdot 1 \cdot b c}{2 \cdot 1}

化简

(- 1)^{2} - 4 \cdot 1 \cdot b c : 1 - 4 b c

a_{1, 2} = \frac{- ( - 1 ) \pm 1 - 4 b c}{2 \cdot 1}

将解分隔开

a_{1} = \frac{- ( - 1 ) + 1 - 4 b c}{2 \cdot 1}, a_{2} = \frac{- ( - 1 ) - 1 - 4 b c}{2 \cdot 1}

a = \frac{- ( - 1 ) + 1 - 4 b c}{2 \cdot 1} : \frac{1 + 1 - 4 b c}{2}

a = \frac{- ( - 1 ) - 1 - 4 b c}{2 \cdot 1} : \frac{1 - 1 - 4 b c}{2}

二次方程组的解是:

a = \frac{1 + 1 - 4 b c}{2}, a = \frac{1 - 1 - 4 b c}{2}

作图

流行的例子

2 x^{2} + x - \frac{1}{8} = 0

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(2x-2)^2-(x+3)^2=-5

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y = 2 y^{2}

a x^{2} + x + c = 0