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受欢迎的代数 >

x^2+(m-3)x+m+1=0

解答

x^{2} + (m - 3) x + m + 1 = 0

解答

x = \frac{- m + 3 + m ^{2} - 10 m + 5}{2}, x = \frac{- m + 3 - m ^{2} - 10 m + 5}{2}

求解步骤

x^{2} + (m - 3) x + m + 1 = 0

使用求根公式求解

x_{1, 2} = \frac{- ( m - 3 ) \pm ( m - 3 ) ^{2} - 4 \cdot 1 \cdot ( m + 1 )}{2 \cdot 1}

化简

(m - 3)^{2} - 4 \cdot 1 \cdot (m + 1) : m^{2} - 10 m + 5

x_{1, 2} = \frac{- ( m - 3 ) \pm m ^{2} - 10 m + 5}{2 \cdot 1}

将解分隔开

x_{1} = \frac{- ( m - 3 ) + m ^{2} - 10 m + 5}{2 \cdot 1}, x_{2} = \frac{- ( m - 3 ) - m ^{2} - 10 m + 5}{2 \cdot 1}

x = \frac{- ( m - 3 ) + m ^{2} - 10 m + 5}{2 \cdot 1} : \frac{- m + 3 + m ^{2} - 10 m + 5}{2}

x = \frac{- ( m - 3 ) - m ^{2} - 10 m + 5}{2 \cdot 1} : \frac{- m + 3 - m ^{2} - 10 m + 5}{2}

二次方程组的解是:

x = \frac{- m + 3 + m ^{2} - 10 m + 5}{2}, x = \frac{- m + 3 - m ^{2} - 10 m + 5}{2}

作图

流行的例子

-5b^2+9b+13=-6b^2

- 5 b^{2} + 9 b + 13 = - 6 b^{2}

- x^{2} + 5 x + 4 = 6

- 8 + 13 x^{2} = 0

50 x^{2} = 70

(x - 3) \cdot (x + 2) = 0