化简 e^{-(t/5)^2}

解答

化简

e^{- (\frac{t}{5})^{2}}

\frac{1}{e ^{\frac{t ^{2}}{25}}}

求解步骤

e^{- (\frac{t}{5})^{2}}

使用指数法则:

a^{- b} = \frac{1}{a ^{b}}

= \frac{1}{e ^{(\frac{t}{5})^{2}}}

e^{(\frac{t}{5})^{2}} = e^{\frac{t ^{2}}{5 ^{2}}}

= \frac{1}{e ^{\frac{t ^{2}}{5 ^{2}}}}

5^{2} = 25

= \frac{1}{e ^{\frac{t ^{2}}{25}}}

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