What are the solutions to the equation x^2-4=-4x ?

The solutions to the equation x^2-4=-4x are x=2(sqrt(2)-1),x=-2(1+sqrt(2))

Find the zeros of x^2-4=-4x

The zeros of x^2-4=-4x are x=2(sqrt(2)-1),x=-2(1+sqrt(2))

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x^{2} - 4 = - 4 x

x = 2 (2 - 1), x = - 2 (1 + 2)

Decimal Notation

x = 0.82842 \dots, x = - 4.82842 \dots

Solution steps

x^{2} - 4 = - 4 x

Move

4 x

to the left side

x^{2} - 4 + 4 x = 0

Write in the standard form

a x^{2} + b x + c = 0

x^{2} + 4 x - 4 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- 4 \pm 4 ^{2} - 4 \cdot 1 \cdot ( - 4 )}{2 \cdot 1}

4^{2} - 4 \cdot 1 \cdot (- 4) = 42

x_{1, 2} = \frac{- 4 \pm 4 2}{2 \cdot 1}

Separate the solutions

x_{1} = \frac{- 4 + 4 2}{2 \cdot 1}, x_{2} = \frac{- 4 - 4 2}{2 \cdot 1}

x = \frac{- 4 + 4 2}{2 \cdot 1} : 2 (2 - 1)

x = \frac{- 4 - 4 2}{2 \cdot 1} : - 2 (1 + 2)

The solutions to the quadratic equation are:

x = 2 (2 - 1), x = - 2 (1 + 2)

2 x - 3 (5 x - 1) < 3 - (13 x + 8)

x^{2} - 64 x = 0

2 x + 16 < x + 25

x^{3} - 4 x^{2} - 16 x + 64 < 0

10 y^{2} + 11 y - 6 = 0

What are the solutions to the equation x^2-4=-4x ?
The solutions to the equation x^2-4=-4x are x=2(sqrt(2)-1),x=-2(1+sqrt(2))
Find the zeros of x^2-4=-4x
The zeros of x^2-4=-4x are x=2(sqrt(2)-1),x=-2(1+sqrt(2))