vereinfachen (0m)+(7.8 m/s)(2.45s)-1/2 (-9.8(m/s)^2)(2.45s)^2

Lösung

vereinfachen

(0 m) + (7.8 \frac{m}{s}) (2.45 s) - \frac{1}{2} (- 9.8 (\frac{m}{s})^{2}) (2.45 s)^{2}

\frac{1911 m}{100} + \frac{23529.8 m ^{2}}{800}

Schritte zur Lösung

(0 \cdot m) + (7.8 \cdot \frac{m}{s}) (2.45 s) - \frac{1}{2} (- 9.8 (\frac{m}{s})^{2}) (2.45 s)^{2}

Apply rule:

(a) = a

(0 \cdot m) = 0 \cdot m

= 0 \cdot m + 7.8 \cdot \frac{m}{s} \cdot 2.45 s - \frac{1}{2} (- 9.8 (\frac{m}{s})^{2}) (2.45 s)^{2}

0 \cdot m = 0

7.8 \cdot \frac{m}{s} \cdot 2.45 s = 19.11 m

\frac{1}{2} (- 9.8 (\frac{m}{s})^{2}) (2.45 s)^{2} = - \frac{23529.8 m ^{2}}{800}

= 0 + 19.11 m - (- \frac{23529.8 m ^{2}}{800})

Füge zusammen:

0 + 19.11 m - (- \frac{23529.8 m ^{2}}{800}) : 19.11 m + \frac{23529.8 m ^{2}}{800}

= 19.11 m + \frac{23529.8 m ^{2}}{800}

19.11 = \frac{1911}{100}

= \frac{1911}{100} m + \frac{23529.8 m ^{2}}{800}

Vereinfache

\frac{1911}{100} m : \frac{1911 m}{100}

= \frac{1911 m}{100} + \frac{23529.8 m ^{2}}{800}

(x - 1) (x - 4) = 0

s im pl i f y ln (e^{9})

s im pl i f y \frac{2}{2 ^{6}}

s im pl i f y (a^{3})^{4}

3 x + 2 = - 55