What are the solutions to the equation 9x^2-4x=0 ?

The solutions to the equation 9x^2-4x=0 are x= 4/9 ,x=0

Find the zeros of 9x^2-4x=0

The zeros of 9x^2-4x=0 are x= 4/9 ,x=0

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9 x^{2} - 4 x = 0

x = \frac{4}{9}, x = 0

Decimal Notation

x = 0.44444 \dots, x = 0

Solution steps

9 x^{2} - 4 x = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- ( - 4 ) \pm ( - 4 ) ^{2} - 4 \cdot 9 \cdot 0}{2 \cdot 9}

(- 4)^{2} - 4 \cdot 9 \cdot 0 = 4

x_{1, 2} = \frac{- ( - 4 ) \pm 4}{2 \cdot 9}

Separate the solutions

x_{1} = \frac{- ( - 4 ) + 4}{2 \cdot 9}, x_{2} = \frac{- ( - 4 ) - 4}{2 \cdot 9}

x = \frac{- ( - 4 ) + 4}{2 \cdot 9} : \frac{4}{9}

x = \frac{- ( - 4 ) - 4}{2 \cdot 9} : 0

The solutions to the quadratic equation are:

x = \frac{4}{9}, x = 0

f = \frac{5 ( 1 )}{( 1 ) ^{2} - 4}

\frac{3}{2} - 2 x > \frac{1}{2}

- 2 (- 3 x + 4) + 3 x - 3 = - 29

12 g = 12 (32 g - 1) + 11

42 = d^{2} - 22

What are the solutions to the equation 9x^2-4x=0 ?
The solutions to the equation 9x^2-4x=0 are x= 4/9 ,x=0
Find the zeros of 9x^2-4x=0
The zeros of 9x^2-4x=0 are x= 4/9 ,x=0