展开 ((3-2y)^2)/2

解答

展开

\frac{( 3 - 2 y ) ^{2}}{2}

2 y^{2} - 6 y + \frac{9}{2}

求解步骤

\frac{( 3 - 2 y ) ^{2}}{2}

(3 - 2 y)^{2} = 9 - 12 y + 4 y^{2}

= \frac{9 - 12 y + 4 y ^{2}}{2}

使用分式法则:

\frac{a \pm b}{c} = \frac{a}{c} \pm \frac{b}{c}

\frac{9 - 12 y + 4 y ^{2}}{2} = \frac{9}{2} - \frac{12 y}{2} + \frac{4 y ^{2}}{2}

= \frac{9}{2} - \frac{12 y}{2} + \frac{4 y ^{2}}{2}

数字相除:

\frac{12}{2} = 6

= \frac{9}{2} - 6 y + \frac{4 y ^{2}}{2}

数字相除:

\frac{4}{2} = 2

= \frac{9}{2} - 6 y + 2 y^{2}

改写为标准形式

= 2 y^{2} - 6 y + \frac{9}{2}

e x p an d (x - 3) sin (π x)

e x p an d \frac{( x + 2 ) ( x + 1 )}{( 5 x + 7 )}

e x p an d e^{a^{3}} \cdot (3 a^{2} x - a^{2})

e x p an d (a + b, 0) (a - b, 0)

e x p an d \frac{1}{2 + x}