因式分解 (s^2+4)^2-5

解答

因式分解

(s^{2} + 4)^{2} - 5

s^{4} + 8 s^{2} + 11

求解步骤

(s^{2} + 4)^{2} - 5

(s^{2} + 4)^{2} : s^{4} + 8 s^{2} + 16

= s^{4} + 8 s^{2} + 16 - 5

数字相加/相减:

16 - 5 = 11

= s^{4} + 8 s^{2} + 11

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