faktorisieren 6(x+2y)^2+13(x+2y)-5

Lösung

faktorisieren

6 (x + 2 y)^{2} + 13 (x + 2 y) - 5

(3 (x + 2 y) - 1) (2 (x + 2 y) + 5)

Schritte zur Lösung

6 (x + 2 y)^{2} + 13 (x + 2 y) - 5

Zerlege die Ausdrücke in Gruppen

= (6 (x + 2 y)^{2} - 2 (x + 2 y)) + (15 (x + 2 y) - 5)

Klammere

2 (x + 2 y)

aus

6 (x + 2 y)^{2} - 2 (x + 2 y)

aus

: 2 (x + 2 y) (3 (x + 2 y) - 1)

Klammere

5

aus

15 (x + 2 y) - 5

aus

: 5 (3 (x + 2 y) - 1)

= 2 (x + 2 y) (3 (x + 2 y) - 1) + 5 (3 (x + 2 y) - 1)

Klammere gleiche Terme aus

3 (x + 2 y) - 1

= (3 (x + 2 y) - 1) (2 (x + 2 y) + 5)

f (s) = (d s)^{2}

f a c t or e^{x^{2} - y^{2}} cos (2 x y)

f a c t or y^{3} + 3 x y^{2} \frac{d y}{d x}

f a c t or 6 cos (π x + 4 π t) + 6 cos (π x - 4 π t)

f a c t or H + He