What are the solutions to the equation 3(x-1)^2-162=0 ?

The solutions to the equation 3(x-1)^2-162=0 are x=3sqrt(6)+1,x=-3sqrt(6)+1

Find the zeros of 3(x-1)^2-162=0

The zeros of 3(x-1)^2-162=0 are x=3sqrt(6)+1,x=-3sqrt(6)+1

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3 (x - 1)^{2} - 162 = 0

x = 36 + 1, x = - 36 + 1

Decimal Notation

x = 8.34846 \dots, x = - 6.34846 \dots

Solution steps

3 (x - 1)^{2} - 162 = 0

Move

162

to the right side

3 (x - 1)^{2} = 162

Divide both sides by

3

(x - 1)^{2} = 54

For

(g (x))^{2} = f (a)

the solutions are

g (x) = f (a), - f (a)

Solve

x - 1 = 54 : x = 36 + 1

Solve

x - 1 = - 54 : x = - 36 + 1

The solutions to the quadratic equation are:

x = 36 + 1, x = - 36 + 1

12 r^{2} - 11 r - 15 = 0

s^{2} + 3 s + 5 = 0

6 \cdot 0.5

\frac{3}{5} x - 1 = 2

g (f (2))

What are the solutions to the equation 3(x-1)^2-162=0 ?
The solutions to the equation 3(x-1)^2-162=0 are x=3sqrt(6)+1,x=-3sqrt(6)+1
Find the zeros of 3(x-1)^2-162=0
The zeros of 3(x-1)^2-162=0 are x=3sqrt(6)+1,x=-3sqrt(6)+1