2x^2+10x-72=0

解

2 x^{2} + 10 x - 72 = 0

x = 4, x = - 9

解答ステップ

2 x^{2} + 10 x - 72 = 0

解くとthe二次式

x_{1, 2} = \frac{- 10 \pm 1 0 ^{2} - 4 \cdot 2 ( - 72 )}{2 \cdot 2}

1 0^{2} - 4 \cdot 2 (- 72) = 26

x_{1, 2} = \frac{- 10 \pm 26}{2 \cdot 2}

解を分離する

x_{1} = \frac{- 10 + 26}{2 \cdot 2}, x_{2} = \frac{- 10 - 26}{2 \cdot 2}

x = \frac{- 10 + 26}{2 \cdot 2} : 4

x = \frac{- 10 - 26}{2 \cdot 2} : - 9

二次equationの解:

x = 4, x = - 9