s=2(n+1),c=3n-4

解答

s = 2 (n + 1), c = 3 n - 4

c = 3 n - 4, s = 2 (n + 1)

求解步骤

[s = 2 (n + 1) c = 3 n - 4]

[c = 3 n - 4]

方程组的解为:

c = 3 n - 4, s = 2 (n + 1)

p (x) = 3, x + 1 x = - \frac{1}{3}

5 x + 6 y = 20, 4 x - 3 y = - 23

x - y = 1, x + y = 9

2 x + 3 y = 1, - x + y = 1

x + y = 10, x - y = - 7