What are the solutions to the equation 2x^2-5x=0 ?

The solutions to the equation 2x^2-5x=0 are x= 5/2 ,x=0

Find the zeros of 2x^2-5x=0

The zeros of 2x^2-5x=0 are x= 5/2 ,x=0

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2 x^{2} - 5 x = 0

x = \frac{5}{2}, x = 0

Decimal Notation

x = 2.5, x = 0

Solution steps

2 x^{2} - 5 x = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- ( - 5 ) \pm ( - 5 ) ^{2} - 4 \cdot 2 \cdot 0}{2 \cdot 2}

(- 5)^{2} - 4 \cdot 2 \cdot 0 = 5

x_{1, 2} = \frac{- ( - 5 ) \pm 5}{2 \cdot 2}

Separate the solutions

x_{1} = \frac{- ( - 5 ) + 5}{2 \cdot 2}, x_{2} = \frac{- ( - 5 ) - 5}{2 \cdot 2}

x = \frac{- ( - 5 ) + 5}{2 \cdot 2} : \frac{5}{2}

x = \frac{- ( - 5 ) - 5}{2 \cdot 2} : 0

The solutions to the quadratic equation are:

x = \frac{5}{2}, x = 0

x^{2} + 12 x + 35 \geq 0

x (x + 2) (x - 2) \leq 0

- 3 x^{2} + 18 x - 15 = 0

\frac{1}{25} - 9 z^{2}

- 8 (w - 6) = 32

What are the solutions to the equation 2x^2-5x=0 ?
The solutions to the equation 2x^2-5x=0 are x= 5/2 ,x=0
Find the zeros of 2x^2-5x=0
The zeros of 2x^2-5x=0 are x= 5/2 ,x=0