(x^2+1)/((x^2)-5(a+1/x)+2)=0

解

\frac{x ^{2} + 1}{( x ^{2} ) - 5 ( a + \frac{1}{x} ) + 2} = 0

x = i, x = - i; x^{2} - 5 (a + \frac{1}{x}) + 2 \neq = 0

解答ステップ

\frac{x ^{2} + 1}{( x ^{2} ) - 5 ( a + \frac{1}{x} ) + 2} = 0

簡素化

\frac{x ^{2} + 1}{( x ^{2} ) - 5 ( a + \frac{1}{x} ) + 2} : \frac{x ^{2} + 1}{x ^{2} - 5 ( a + \frac{1}{x} ) + 2}

\frac{x ^{2} + 1}{x ^{2} - 5 ( a + \frac{1}{x} ) + 2} = 0

\frac{f ( x )}{g ( x )} = 0 \Rightarrow f (x) = 0

x^{2} + 1 = 0

解く

x^{2} + 1 = 0 : x = i, x = - i

x = i, x = - i; x^{2} - 5 (a + \frac{1}{x}) + 2 \neq = 0