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受欢迎的代数 >

solvefor b,a=2-1/((1+b))

解答

求解

b, a = 2 - \frac{1}{( 1 + b )}

解答

b = \frac{- a + 1}{a - 2}; a \neq = 2

求解步骤

a = 2 - \frac{1}{( 1 + b )}

将

2

para o lado esquerdo

a - 2 = - \frac{1}{1 + b}

在两边乘以

1 + b

a (1 + b) - 2 (1 + b) = - 1

乘开

a (1 + b) : a + ba

a + ba - 2 (1 + b) = - 1

乘开

- 2 (1 + b) : - 2 - 2 b

a + ba - 2 - 2 b = - 1

将

a

到右边

ba - 2 - 2 b = - 1 - a

将

2

到右边

ba - 2 b = - a + 1

分解

ba - 2 b : b (a - 2)

b (a - 2) = - a + 1

两边除以

a - 2; a \neq = 2

b = \frac{- a + 1}{a - 2}; a \neq = 2

作图

流行的例子

7/((10x))= 3/(20+5)

\frac{7}{( 10 x )} = \frac{3}{20 + 5}

\frac{b}{4} = \frac{a}{x + 6}

1/x+1/x-4= 2/(x^2)-4x

\frac{1}{x} + \frac{1}{x} - 4 = \frac{2}{x ^{2}} - 4 x

(x-4}{x-2}=\frac{-3)/4

\frac{x - 4}{x - 2} = \frac{- 3}{4}

((1)x+1)/x = 21/20

\frac{( 1 ) x + 1}{x} = \frac{21}{20}