2=a^x

Lösung

2 = a^{x}

x = \frac{ln ( 2 )}{ln ( a )}

Schritte zur Lösung

2 = a^{x}

Wende Exponentenregel an

ln (2) = x ln (a)

Löse

ln (2) = x ln (a) : x = \frac{ln ( 2 )}{ln ( a )}

x = \frac{ln ( 2 )}{ln ( a )}

so l v e f or x, 2^{x} + 2^{y} = 2^{y} + 4^{x}

3^{x - 3} = 2 x - 5

4 x^{3} \cdot e^{- 3 x} - 3 x^{4} \cdot e^{- 3 x} = 0

\frac{2 ^{x + 5}}{3 ^{x + 5}} = 0.01156

3^{x - 1} = 27