What are the solutions to the equation 4x^2+12x+9=0 ?

The solutions to the equation 4x^2+12x+9=0 are x=-3/2

Find the zeros of 4x^2+12x+9=0

The zeros of 4x^2+12x+9=0 are x=-3/2

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4 x^{2} + 12 x + 9 = 0

x = - \frac{3}{2}

Decimal Notation

x = - 1.5

Solution steps

4 x^{2} + 12 x + 9 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- 12 \pm 1 2 ^{2} - 4 \cdot 4 \cdot 9}{2 \cdot 4}

1 2^{2} - 4 \cdot 4 \cdot 9 = 0

x_{1, 2} = \frac{- 12 \pm 0}{2 \cdot 4}

x = \frac{- 12}{2 \cdot 4}

\frac{- 12}{2 \cdot 4} = - \frac{3}{2}

x = - \frac{3}{2}

The solution to the quadratic equation is:

x = - \frac{3}{2}

(- \frac{1}{2 7 - x})^{2}

- 9 \leq \frac{13}{4} x - 1 \leq - 1

- \frac{3}{5} + 1

x^{2} + x + 4 \geq 0

What are the solutions to the equation 4x^2+12x+9=0 ?
The solutions to the equation 4x^2+12x+9=0 are x=-3/2
Find the zeros of 4x^2+12x+9=0
The zeros of 4x^2+12x+9=0 are x=-3/2