(b-b)x^2+(c-a)x+(a-b)=0

解

(b - b) \cdot x^{2} + (c - a) \cdot x + (a - b) = 0

x = \frac{- a + b}{c - a}; c - a \neq = 0

解答ステップ

(b - b) x^{2} + (c - a) x + (a - b) = 0

簡素化

(b - b) x^{2} + (c - a) x + (a - b) : x (c - a) + a - b

x (c - a) + a - b = 0

a

を右側に移動します

x (c - a) - b = - a

b

を右側に移動します

x (c - a) = - a + b

以下で両辺を割る

c - a; c - a \neq = 0

x = \frac{- a + b}{c - a}; c - a \neq = 0