What are the solutions to the equation x^2+4=7x-3 ?

The solutions to the equation x^2+4=7x-3 are x=(7+sqrt(21))/2 ,x=(7-sqrt(21))/2

Find the zeros of x^2+4=7x-3

The zeros of x^2+4=7x-3 are x=(7+sqrt(21))/2 ,x=(7-sqrt(21))/2

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

x^{2} + 4 = 7 x - 3

x = \frac{7 + 21}{2}, x = \frac{7 - 21}{2}

Decimal Notation

x = 5.79128 \dots, x = 1.20871 \dots

Solution steps

x^{2} + 4 = 7 x - 3

Move

3

to the left side

x^{2} + 7 = 7 x

Move

7 x

to the left side

x^{2} + 7 - 7 x = 0

Write in the standard form

a x^{2} + b x + c = 0

x^{2} - 7 x + 7 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- ( - 7 ) \pm ( - 7 ) ^{2} - 4 \cdot 1 \cdot 7}{2 \cdot 1}

(- 7)^{2} - 4 \cdot 1 \cdot 7 = 21

x_{1, 2} = \frac{- ( - 7 ) \pm 21}{2 \cdot 1}

Separate the solutions

x_{1} = \frac{- ( - 7 ) + 21}{2 \cdot 1}, x_{2} = \frac{- ( - 7 ) - 21}{2 \cdot 1}

x = \frac{- ( - 7 ) + 21}{2 \cdot 1} : \frac{7 + 21}{2}

x = \frac{- ( - 7 ) - 21}{2 \cdot 1} : \frac{7 - 21}{2}

The solutions to the quadratic equation are:

x = \frac{7 + 21}{2}, x = \frac{7 - 21}{2}

(\frac{4}{7})^{- 1}

8 x^{2} - 43 x + 15

(\frac{12}{25} \cdot \frac{15}{7}) \div \frac{20}{7}

3 d^{2} + d - 10 = 0

\frac{1}{4} (5)

What are the solutions to the equation x^2+4=7x-3 ?
The solutions to the equation x^2+4=7x-3 are x=(7+sqrt(21))/2 ,x=(7-sqrt(21))/2
Find the zeros of x^2+4=7x-3
The zeros of x^2+4=7x-3 are x=(7+sqrt(21))/2 ,x=(7-sqrt(21))/2