化简 (3*a/2+b/4-2c)^2

解答

化简

(3 \cdot \frac{a}{2} + \frac{b}{4} - 2 c)^{2}

\frac{( - 8 c + 6 a + b ) ^{2}}{16}

求解步骤

(3 \cdot \frac{a}{2} + \frac{b}{4} - 2 c)^{2}

化简

3 \cdot \frac{a}{2} + \frac{b}{4} - 2 c : \frac{- 8 c + 6 a + b}{4}

= (\frac{- 8 c + 6 a + b}{4})^{2}

使用指数法则:

(\frac{a}{b})^{c} = \frac{a ^{c}}{b ^{c}}

= \frac{( - 8 c + 6 a + b ) ^{2}}{4 ^{2}}

4^{2} = 16

= \frac{( - 8 c + 6 a + b ) ^{2}}{16}

s im pl i f y (\frac{2}{3} a - 3 \frac{b}{2} - 4 \frac{c}{5})^{2}

e x p an d (x^{3} - 2 x^{2} + x - 1) (5 - x)

f a c t or - x^{2} + 2 x + 15

s im pl i f y 2 sin (x) - (\frac{( 4 sin ( x ) - cos ( x ) )}{2})

f a c t or 16 x^{4} - 54 y^{3}