faktorisieren 16x^4+8x^3-2x-1

Lösung

faktorisieren

16 x^{4} + 8 x^{3} - 2 x - 1

(2 x + 1) (2 x - 1) (4 x^{2} + 2 x + 1)

Schritte zur Lösung

16 x^{4} + 8 x^{3} - 2 x - 1

= (16 x^{4} + 8 x^{3}) + (- 2 x - 1)

Klammere

8 x^{3}

aus

16 x^{4} + 8 x^{3}

aus

: 8 x^{3} (2 x + 1)

Klammere

- 1

aus

- 2 x - 1

aus

: - (2 x + 1)

= 8 x^{3} (2 x + 1) - (2 x + 1)

Klammere gleiche Terme aus

(2 x + 1) : (2 x + 1) (8 x^{3} - 1)

= (2 x + 1) (8 x^{3} - 1)

Faktorisiere

8 x^{3} - 1 : (2 x - 1) (2^{2} x^{2} + 2 x + 1)

= (2 x + 1) (2 x - 1) (2^{2} x^{2} + 2 x + 1)

2^{2} = 4

= (2 x + 1) (2 x - 1) (4 x^{2} + 2 x + 1)

f a c t or 14 x^{6} - 45 x^{3} y^{3} - 14 y^{6}

e x p an d (3 y + 2 x)^{10}

e x p an d (2 a + b - c)^{3}

s im pl i f y \frac{10 ( r ^{35} p ^{9} )}{( - q )}

e x p an d (1 - x) (1 + x) (1 + x^{2}) (1 + x^{4})