faktorisieren 10x^4-13x^3+8x^2-8x+3

Lösung

faktorisieren

10 x^{4} - 13 x^{3} + 8 x^{2} - 8 x + 3

(x - 1) (2 x - 1) (5 x^{2} + x + 3)

Schritte zur Lösung

10 x^{4} - 13 x^{3} + 8 x^{2} - 8 x + 3

Wende den rationalen Nullstellentest an

= (x - 1) \frac{10 x ^{4} - 13 x ^{3} + 8 x ^{2} - 8 x + 3}{x - 1}

\frac{10 x ^{4} - 13 x ^{3} + 8 x ^{2} - 8 x + 3}{x - 1} = 10 x^{3} - 3 x^{2} + 5 x - 3

= (x - 1) (10 x^{3} - 3 x^{2} + 5 x - 3)

Faktorisiere

10 x^{3} - 3 x^{2} + 5 x - 3 : (2 x - 1) (5 x^{2} + x + 3)

= (x - 1) (2 x - 1) (5 x^{2} + x + 3)

s im pl i f y \frac{- y}{2}

s im pl i f y x^{2} - (\frac{a + 1}{a}) x + 1

s im pl i f y (\frac{( 256 a ^{16} )}{( 81 b ^{4} )})^{\frac{- 3}{4}}

f a c t or a^{4} + a^{2} \cdot b^{2} + b^{4}

f a c t or x^{4} - 3 x - 2