faktorisieren 4x^3-12x^2-9x-1

Lösung

faktorisieren

4 x^{3} - 12 x^{2} - 9 x - 1

(2 x + 1) (2 x^{2} - 7 x - 1)

Schritte zur Lösung

4 x^{3} - 12 x^{2} - 9 x - 1

Wende den rationalen Nullstellentest an

= (2 x + 1) \frac{4 x ^{3} - 12 x ^{2} - 9 x - 1}{2 x + 1}

\frac{4 x ^{3} - 12 x ^{2} - 9 x - 1}{2 x + 1} = 2 x^{2} - 7 x - 1

= (2 x + 1) (2 x^{2} - 7 x - 1)

12 > 14 + x

x^{2} + 4 x - 10 = 0

45 = - 5 k

∣ 5 x - 1 ∣ - 11 = - 1

12 (3 - x) = 15