a=12h(b^1+b^2)

解答

a = 12 h (b^{1} + b^{2})

h = \frac{a}{12 ( b + b ^{2} )}; b \neq = 0, b \neq = - 1

求解步骤

a = 12 h (b^{1} + b^{2})

交换两边

12 h (b^{1} + b^{2}) = a

两边除以

12 (b^{1} + b^{2}); b \neq = 0, b \neq = - 1

h = \frac{a}{12 ( b + b ^{2} )}; b \neq = 0, b \neq = - 1

x - 11 = 5

5 = x \cdot \frac{222.22}{1000 + 222.22}

\frac{3 x + 1}{2} + \frac{1 - x}{6} = \frac{5 x + 4}{4}

(+ 5) (+ 3) = + 15

(x - 2) + (x + 3) + (x + 7) + (x - 4) = 360