What are the solutions to the equation x^2-2sqrt(2)x+2=0 ?

The solutions to the equation x^2-2sqrt(2)x+2=0 are x=sqrt(2)

Find the zeros of x^2-2sqrt(2)x+2=0

The zeros of x^2-2sqrt(2)x+2=0 are x=sqrt(2)

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x^{2} - 22 x + 2 = 0

x = 2

Decimal Notation

x = 1.41421 \dots

Solution steps

x^{2} - 22 x + 2 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- ( - 2 2 ) \pm ( - 2 2 ) ^{2} - 4 \cdot 1 \cdot 2}{2 \cdot 1}

(- 22)^{2} - 4 \cdot 1 \cdot 2 = 0

x_{1, 2} = \frac{- ( - 2 2 ) \pm 0}{2 \cdot 1}

x = \frac{- ( - 2 2 )}{2 \cdot 1}

\frac{- ( - 2 2 )}{2 \cdot 1} = 2

x = 2

The solution to the quadratic equation is:

x = 2

\frac{2 x ^{2} y ^{4}}{2 x y ^{4}}

12 x^{2} - 22 x + 6

3 x^{2} + x - 2

2^{- \frac{1}{3}}

x^{2} = 1^{2} + 4^{2} + 8^{2}

What are the solutions to the equation x^2-2sqrt(2)x+2=0 ?
The solutions to the equation x^2-2sqrt(2)x+2=0 are x=sqrt(2)
Find the zeros of x^2-2sqrt(2)x+2=0
The zeros of x^2-2sqrt(2)x+2=0 are x=sqrt(2)