a(x+b)+b(x-a)+x(a-b)=a^2

Lösung

a (x + b) + b (x - a) + x (a - b) = a^{2}

x = \frac{a}{2}; a \neq = 0

Schritte zur Lösung

a (x + b) + b (x - a) + x (a - b) = a^{2}

Schreibe

a (x + b) + b (x - a) + x (a - b)

um:

2 a x

2 a x = a^{2}

Teile beide Seiten durch

2 a; a \neq = 0

x = \frac{a}{2}; a \neq = 0

1 + x = - 4

x + 19 = - 2 x - 2

so l v e f or y, x = \frac{1}{2} y

G (p) = 6 p - p^{2}

- 3 = x + 10