What are the solutions to the equation (2w-3)w=27 ?

The solutions to the equation (2w-3)w=27 are w= 9/2 ,w=-3

Find the zeros of (2w-3)w=27

The zeros of (2w-3)w=27 are w= 9/2 ,w=-3

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(2 w - 3) w = 27

w = \frac{9}{2}, w = - 3

Decimal Notation

w = 4.5, w = - 3

Solution steps

(2 w - 3) w = 27

Expand

(2 w - 3) w : 2 w^{2} - 3 w

2 w^{2} - 3 w = 27

Move

27

to the left side

2 w^{2} - 3 w - 27 = 0

Solve with the quadratic formula

w_{1, 2} = \frac{- ( - 3 ) \pm ( - 3 ) ^{2} - 4 \cdot 2 ( - 27 )}{2 \cdot 2}

(- 3)^{2} - 4 \cdot 2 (- 27) = 15

w_{1, 2} = \frac{- ( - 3 ) \pm 15}{2 \cdot 2}

Separate the solutions

w_{1} = \frac{- ( - 3 ) + 15}{2 \cdot 2}, w_{2} = \frac{- ( - 3 ) - 15}{2 \cdot 2}

w = \frac{- ( - 3 ) + 15}{2 \cdot 2} : \frac{9}{2}

w = \frac{- ( - 3 ) - 15}{2 \cdot 2} : - 3

The solutions to the quadratic equation are:

w = \frac{9}{2}, w = - 3

5 (9 + 6 x) + 15 (12 + 13 x) = 450

(1 - x^{2})^{\frac{3}{2}}

2 - \frac{4}{9} x = \frac{5}{6}

- 0.121 + 7.865 > 7.9 y + 0.019

\frac{1}{2} + \frac{4}{5}

What are the solutions to the equation (2w-3)w=27 ?
The solutions to the equation (2w-3)w=27 are w= 9/2 ,w=-3
Find the zeros of (2w-3)w=27
The zeros of (2w-3)w=27 are w= 9/2 ,w=-3