What are the solutions to the equation y^2-14y+49=5 ?

The solutions to the equation y^2-14y+49=5 are y=7+sqrt(5),y=7-sqrt(5)

Find the zeros of y^2-14y+49=5

The zeros of y^2-14y+49=5 are y=7+sqrt(5),y=7-sqrt(5)

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y^{2} - 14 y + 49 = 5

y = 7 + 5, y = 7 - 5

Decimal Notation

y = 9.23606 \dots, y = 4.76393 \dots

Solution steps

y^{2} - 14 y + 49 = 5

Move

5

to the left side

y^{2} - 14 y + 44 = 0

Solve with the quadratic formula

y_{1, 2} = \frac{- ( - 14 ) \pm ( - 14 ) ^{2} - 4 \cdot 1 \cdot 44}{2 \cdot 1}

(- 14)^{2} - 4 \cdot 1 \cdot 44 = 25

y_{1, 2} = \frac{- ( - 14 ) \pm 2 5}{2 \cdot 1}

Separate the solutions

y_{1} = \frac{- ( - 14 ) + 2 5}{2 \cdot 1}, y_{2} = \frac{- ( - 14 ) - 2 5}{2 \cdot 1}

y = \frac{- ( - 14 ) + 2 5}{2 \cdot 1} : 7 + 5

y = \frac{- ( - 14 ) - 2 5}{2 \cdot 1} : 7 - 5

The solutions to the quadratic equation are:

y = 7 + 5, y = 7 - 5

- x < - 1

\frac{3.01 \cdot 1 0 ^{24}}{6.02 \cdot 1 0 ^{23}}

3 (x + 1) = 3 x + 3

x (2 x - 4) = 0

\frac{2 π}{3} \cdot \frac{180}{π}

What are the solutions to the equation y^2-14y+49=5 ?
The solutions to the equation y^2-14y+49=5 are y=7+sqrt(5),y=7-sqrt(5)
Find the zeros of y^2-14y+49=5
The zeros of y^2-14y+49=5 are y=7+sqrt(5),y=7-sqrt(5)