ja

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

人気のある代数 >

3x^2+2x+ax^2+5a+1=0

解

3 x^{2} + 2 x + a x^{2} + 5 a + 1 = 0

解

x = \frac{- 1 + - 5 a ^{2} - 16 a - 2}{3 + a}, x = - \frac{- 5 a ^{2} - 16 a - 2 + 1}{a + 3}; a \neq = - 3

解答ステップ

3 x^{2} + 2 x + a x^{2} + 5 a + 1 = 0

標準的な形式で書く

a x^{2} + b x + c = 0

(3 + a) x^{2} + 2 x + 5 a + 1 = 0

解くとthe二次式

x_{1, 2} = \frac{- 2 \pm 2 ^{2} - 4 ( 3 + a ) ( 5 a + 1 )}{2 ( 3 + a )}

簡素化

2^{2} - 4 (3 + a) (5 a + 1) : 2 - 5 a^{2} - 16 a - 2

x_{1, 2} = \frac{- 2 \pm 2 - 5 a ^{2} - 16 a - 2}{2 ( 3 + a )}; a \neq = - 3

解を分離する

x_{1} = \frac{- 2 + 2 - 5 a ^{2} - 16 a - 2}{2 ( 3 + a )}, x_{2} = \frac{- 2 - 2 - 5 a ^{2} - 16 a - 2}{2 ( 3 + a )}

x = \frac{- 2 + 2 - 5 a ^{2} - 16 a - 2}{2 ( 3 + a )} : \frac{- 1 + - 5 a ^{2} - 16 a - 2}{3 + a}

x = \frac{- 2 - 2 - 5 a ^{2} - 16 a - 2}{2 ( 3 + a )} : - \frac{- 5 a ^{2} - 16 a - 2 + 1}{a + 3}

二次equationの解:

x = \frac{- 1 + - 5 a ^{2} - 16 a - 2}{3 + a}, x = - \frac{- 5 a ^{2} - 16 a - 2 + 1}{a + 3}; a \neq = - 3

グラフ

人気の例

solvefor y,-6y^2-21=s(y^2+w)

so l v e f or y, - 6 y^{2} - 21 = s (y^{2} + w)

completesquare x^2-6x+7

co m pl e t es q u a re x^{2} - 6 x + 7

(x)=2600+2x+0.001x^2

(x) = 2600 + 2 x + 0.001 x^{2}

x^{2} + a x - 2 a^{2} = 0

4x^2-4a^2x-b^4+a^4=0

4 x^{2} - 4 a^{2} x - b^{4} + a^{4} = 0