4m^2+20m+25=0

解

4 m^{2} + 20 m + 25 = 0

m = - \frac{5}{2}

十進法表記

m = - 2.5

解答ステップ

4 m^{2} + 20 m + 25 = 0

解くとthe二次式

m_{1, 2} = \frac{- 20 \pm 2 0 ^{2} - 4 \cdot 4 \cdot 25}{2 \cdot 4}

2 0^{2} - 4 \cdot 4 \cdot 25 = 0

m_{1, 2} = \frac{- 20 \pm 0}{2 \cdot 4}

m = \frac{- 20}{2 \cdot 4}

\frac{- 20}{2 \cdot 4} = - \frac{5}{2}

m = - \frac{5}{2}

二次equationの解:

m = - \frac{5}{2}