What are the solutions to the equation 36x^2-54x-36=0 ?

The solutions to the equation 36x^2-54x-36=0 are x=2,x=-1/2

Find the zeros of 36x^2-54x-36=0

The zeros of 36x^2-54x-36=0 are x=2,x=-1/2

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36 x^{2} - 54 x - 36 = 0

x = 2, x = - \frac{1}{2}

Solution steps

36 x^{2} - 54 x - 36 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- ( - 54 ) \pm ( - 54 ) ^{2} - 4 \cdot 36 ( - 36 )}{2 \cdot 36}

(- 54)^{2} - 4 \cdot 36 (- 36) = 90

x_{1, 2} = \frac{- ( - 54 ) \pm 90}{2 \cdot 36}

Separate the solutions

x_{1} = \frac{- ( - 54 ) + 90}{2 \cdot 36}, x_{2} = \frac{- ( - 54 ) - 90}{2 \cdot 36}

x = \frac{- ( - 54 ) + 90}{2 \cdot 36} : 2

x = \frac{- ( - 54 ) - 90}{2 \cdot 36} : - \frac{1}{2}

The solutions to the quadratic equation are:

x = 2, x = - \frac{1}{2}

\frac{3 2}{2}

56

- 7 x + 1 \geq 22 or - 10 x + 41 \geq 81

\frac{7}{8} x \geq 6

\frac{19 - 20}{0.53}

What are the solutions to the equation 36x^2-54x-36=0 ?
The solutions to the equation 36x^2-54x-36=0 are x=2,x=-1/2
Find the zeros of 36x^2-54x-36=0
The zeros of 36x^2-54x-36=0 are x=2,x=-1/2