What is (0.1)^2*5*10^{-2} ?

The solution to (0.1)^2*5*10^{-2} is 0.0005

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simplify (0.1)^2510^{-2}

simplify

(0.1)^{2} \cdot 5 \cdot 1 0^{- 2}

0.0005

Solution steps

0. 1^{2} \cdot 5 \cdot 1 0^{- 2}

0. 1^{2} = 0.01

= 0.01 \cdot 5 \cdot 1 0^{- 2}

Apply exponent rule:

a^{- b} = \frac{1}{a ^{b}}

1 0^{- 2} = \frac{1}{1 0 ^{2}}

= 0.01 \cdot 5 \cdot \frac{1}{1 0 ^{2}}

1 0^{2} = 100

= 0.01 \cdot 5 \cdot \frac{1}{100}

Multiply the numbers:

0.01 \cdot 5 = 0.05

= 0.05 \cdot \frac{1}{100}

= \frac{1}{100} \cdot 0.05

\frac{1}{100} \cdot 0.05 = \frac{0.05}{100}

= \frac{0.05}{100}

Divide the numbers:

\frac{0.05}{100} = 0.0005

= 0.0005

(1) (1) (1 - 0.05)^{10}

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