What is e^{-3x}(-2(-5x^2-8x+7)+(-10x-8)) ?

The solution to e^{-3x}(-2(-5x^2-8x+7)+(-10x-8)) is (10x^2+6x-22)/(e^{3x)}

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simplify e^{-3x}(-2(-5x^2-8x+7)+(-10x-8))

simplify

e^{- 3 x} (- 2 (- 5 x^{2} - 8 x + 7) + (- 10 x - 8))

\frac{10 x ^{2} + 6 x - 22}{e ^{3 x}}

Solution steps

e^{- 3 x} (- 2 (- 5 x^{2} - 8 x + 7) + (- 10 x - 8))

Apply exponent rule:

a^{- b} = \frac{1}{a ^{b}}

= \frac{1}{e ^{3 x}} (- 10 x - 2 (- 5 x^{2} - 8 x + 7) - 8)

Multiply fractions:

a \cdot \frac{b}{c} = \frac{a \cdot b}{c}

= \frac{1 \cdot ( - 2 ( - 5 x ^{2} - 8 x + 7 ) - 10 x - 8 )}{e ^{3 x}}

1 \cdot (- 2 (- 5 x^{2} - 8 x + 7) - 10 x - 8) = - 2 (- 5 x^{2} - 8 x + 7) - 10 x - 8

= \frac{- 2 ( - 5 x ^{2} - 8 x + 7 ) - 10 x - 8}{e ^{3 x}}

Expand

- 2 (- 5 x^{2} - 8 x + 7) - 10 x - 8 : 10 x^{2} + 6 x - 22

= \frac{10 x ^{2} + 6 x - 22}{e ^{3 x}}

(3 x^{4}) (5 x^{7})

(6^{2})^{4} \cdot 9^{3} \cdot (\frac{2 ^{6}}{2 ^{4}})^{'}

π (e^{- 2 x})^{2}

2 \cdot 3 \cdot 1 0^{- 4} \cdot e^{- \frac{1}{10}} \cdot 1 0^{- 2}

e^{- \frac{0}{1}}

What is e^{-3x}(-2(-5x^2-8x+7)+(-10x-8)) ?
The solution to e^{-3x}(-2(-5x^2-8x+7)+(-10x-8)) is (10x^2+6x-22)/(e^{3x)}