What is (2e^{-j^{0.3}})(3e^{j^{0.2}}) ?

The solution to (2e^{-j^{0.3}})(3e^{j^{0.2}}) is 6e^{j^{0.2}-j^{0.3}}

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simplify (2e^{-j^{0.3}})(3e^{j^{0.2}})

simplify

(2 e^{- j^{0.3}}) (3 e^{j^{0.2}})

6 e^{j^{0.2} - j^{0.3}}

Solution steps

(2 e^{- j^{0.3}}) (3 e^{j^{0.2}})

Apply exponent rule:

a^{b} \cdot a^{c} = a^{b + c}

e^{- j^{0.3}} e^{j^{0.2}} = e^{- j^{0.3} + j^{0.2}}

= 2 \cdot 3 e^{- j^{0.3} + j^{0.2}}

Multiply the numbers:

2 \cdot 3 = 6

= 6 e^{j^{0.2} - j^{0.3}}

610 \cdot x

e^{- 2} \cdot 3 e^{2}

(2 \cdot 1.92 + \frac{1.2 7 ^{2}}{2} \cdot 9.72) \cdot 1 0^{- 3}

e^{(- s t)} \cdot e^{t}

What is (2e^{-j^{0.3}})(3e^{j^{0.2}}) ?
The solution to (2e^{-j^{0.3}})(3e^{j^{0.2}}) is 6e^{j^{0.2}-j^{0.3}}