What are the solutions to the equation -6x^2-2x+1=0 ?

The solutions to the equation -6x^2-2x+1=0 are x=-(1+sqrt(7))/6 ,x=(sqrt(7)-1)/6

Find the zeros of -6x^2-2x+1=0

The zeros of -6x^2-2x+1=0 are x=-(1+sqrt(7))/6 ,x=(sqrt(7)-1)/6

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

- 6 x^{2} - 2 x + 1 = 0

x = - \frac{1 + 7}{6}, x = \frac{7 - 1}{6}

Solution steps

- 6 x^{2} - 2 x + 1 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- ( - 2 ) \pm ( - 2 ) ^{2} - 4 ( - 6 ) \cdot 1}{2 ( - 6 )}

(- 2)^{2} - 4 (- 6) \cdot 1 = 27

x_{1, 2} = \frac{- ( - 2 ) \pm 2 7}{2 ( - 6 )}

Separate the solutions

x_{1} = \frac{- ( - 2 ) + 2 7}{2 ( - 6 )}, x_{2} = \frac{- ( - 2 ) - 2 7}{2 ( - 6 )}

x = \frac{- ( - 2 ) + 2 7}{2 ( - 6 )} : - \frac{1 + 7}{6}

x = \frac{- ( - 2 ) - 2 7}{2 ( - 6 )} : \frac{7 - 1}{6}

The solutions to the quadratic equation are:

x = - \frac{1 + 7}{6}, x = \frac{7 - 1}{6}

12 y^{2} - 17 y + 6

x^{5} + 1

81 a^{5} b

8 x^{2} + 10 x - 7 = 0

2 (x - 2) = 1 - 3 (x - 4) - 2

What are the solutions to the equation -6x^2-2x+1=0 ?
The solutions to the equation -6x^2-2x+1=0 are x=-(1+sqrt(7))/6 ,x=(sqrt(7)-1)/6
Find the zeros of -6x^2-2x+1=0
The zeros of -6x^2-2x+1=0 are x=-(1+sqrt(7))/6 ,x=(sqrt(7)-1)/6