What is factor 8(x+1)^{-9}+5(x+1)^{-8} ?

The solution to factor 8(x+1)^{-9}+5(x+1)^{-8} is (5x+13)/((1+x)^9)

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factor 8(x+1)^{-9}+5(x+1)^{-8}

factor

8 (x + 1)^{- 9} + 5 (x + 1)^{- 8}

\frac{5 x + 13}{( 1 + x ) ^{9}}

Solution steps

8 (x + 1)^{- 9} + 5 (x + 1)^{- 8}

Apply exponent rule:

a^{b + c} = a^{b} a^{c}

(1 + x)^{- 8} = (1 + x)^{- 9} (1 + x)

= 8 (1 + x)^{- 9} + 5 (1 + x)^{- 9} (1 + x)

Factor out common term

(1 + x)^{- 9}

= (1 + x)^{- 9} (8 + 5 (1 + x))

Expand

5 (x + 1) + 8 : 5 x + 13

= (x + 1)^{- 9} (5 x + 13)

Refine

= \frac{5 x + 13}{( x + 1 ) ^{9}}

3 - 0

∣ x + 2 ∣ = 2

(3 y^{5}) (5 y^{4})

9 r^{2} - 55 r + 6

\frac{x + 2}{x - 4} < \frac{x + 2}{x + 3}

What is factor 8(x+1)^{-9}+5(x+1)^{-8} ?
The solution to factor 8(x+1)^{-9}+5(x+1)^{-8} is (5x+13)/((1+x)^9)