erweitern (y=2,)(x=+1)

Lösung

erweitern

(y = 2,) (x = + 1)

x (2 =, y) = 1 \cdot (2 =, y)

Schritte zur Lösung

(y = 2,) (x = + 1)

= (2 =, y) (= x + 1)

Wende das Distributivgesetz an:

a (b + c) = ab + a c

a = (y = 2,), b = x =, c = 1

(y = 2,) x = (y = 2,) \cdot 1

x (2 =, y) = 1 \cdot (2 =, y)

e x p an d \frac{16 + 6 s ^{2}}{s ^{2} ( s + 4 )}

e x p an d 3 ((x - 4) (x + 2))

e x p an d \frac{( x + 8 ) ( x - 3 )}{( x + 4 ) ( x + 9 )}

e x p an d e^{r x} (r^{2} - 7 r + 6)

e x p an d \frac{1}{8} (2 e^{y} + e^{\frac{y}{4}} + 2 e^{\frac{y}{2}} + 3 e^{\frac{3 y}{4}})