erweitern 3(mx-m-1)^2

Lösung

erweitern

3 (m x - m - 1)^{2}

3 m^{2} x^{2} - 6 m^{2} x - 6 m x + 3 m^{2} + 6 m + 3

Schritte zur Lösung

3 (m x - m - 1)^{2}

(m x - m - 1)^{2} = m^{2} x^{2} - 2 m^{2} x - 2 m x + m^{2} + 2 m + 1

= 3 (m^{2} x^{2} + m^{2} - 2 m^{2} x + 2 m - 2 m x + 1)

Setze Klammern

= 3 m^{2} x^{2} + 3 (- 2 m^{2} x) + 3 (- 2 m x) + 3 m^{2} + 3 \cdot 2 m + 3 \cdot 1

Wende Minus-Plus Regeln an

+ (- a) = - a

= 3 m^{2} x^{2} - 3 \cdot 2 m^{2} x - 3 \cdot 2 m x + 3 m^{2} + 3 \cdot 2 m + 3 \cdot 1

Vereinfache

3 m^{2} x^{2} - 3 \cdot 2 m^{2} x - 3 \cdot 2 m x + 3 m^{2} + 3 \cdot 2 m + 3 \cdot 1 : 3 m^{2} x^{2} - 6 m^{2} x - 6 m x + 3 m^{2} + 6 m + 3

= 3 m^{2} x^{2} - 6 m^{2} x - 6 m x + 3 m^{2} + 6 m + 3

e x p an d \frac{- x ^{2} + 2 x - 3}{( x - 1 ) ^{2}}

e x p an d (e^{2} - 1) u^{2}

e x p an d \frac{( a + x ) ( b + n - x )}{( a + b + n ) ^{2} ( a + b + n + 1 )}

e x p an d (e^{4 x} - e^{- 4 x})^{2}

e x p an d V (0, + 6) F (0, + 10)