erweitern (2x+7)^2pi

Lösung

erweitern

(2 x + 7)^{2} π

4 π x^{2} + 28 π x + 49 π

Schritte zur Lösung

(2 x + 7)^{2} π

(2 x + 7)^{2} = 4 x^{2} + 28 x + 49

= π (4 x^{2} + 28 x + 49)

= π (4 x^{2} + 28 x + 49)

Setze Klammern

= π 4 x^{2} + π 28 x + π 49

= 4 π x^{2} + 28 π x + 49 π

e x p an d \frac{1}{s ( s + a ) ( s + b )}

e x p an d \frac{x ^{2} - 2 x - 1}{( x - 1 ) ^{2} ( x + 2 )}

e x p an d (k + 1)! \cdot (k + 2) - 1

e x p an d \frac{2 - x - 3}{( x + 7 ) ( x - 7 )}

e x p an d \frac{lo g _{10} ( x )}{( lo g _{10} ( x ) + 1 ) ^{2}}