erweitern (n+2)(n+1)!

Lösung

erweitern

(n + 2) (n + 1)!

n (n + 1)! + 2 (n + 1)!

Schritte zur Lösung

(n + 2) (n + 1)!

= (n + 1)! (n + 2)

Wende das Distributivgesetz an:

a (b + c) = ab + a c

a = (n + 1)!, b = n, c = 2

= (n + 1)! n + (n + 1)! \cdot 2

= n (n + 1)! + 2 (n + 1)!

e x p an d \frac{4 x + 0.2}{x ( x + 2 ) ( x - 1.5 )}

e x p an d \frac{1.2541 ( 1 + 0.32 s + 0.0256 s ^{2} )}{s}

e x p an d (1 - x) e^{2 x}

e x p an d \frac{2 x ( x + 4 )}{3}

e x p an d (- \frac{x}{5 - x ^{2}})^{2}