What are the solutions to the equation 9x^2-3x-4=0 ?

The solutions to the equation 9x^2-3x-4=0 are x=(1+sqrt(17))/6 ,x=(1-sqrt(17))/6

Find the zeros of 9x^2-3x-4=0

The zeros of 9x^2-3x-4=0 are x=(1+sqrt(17))/6 ,x=(1-sqrt(17))/6

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9 x^{2} - 3 x - 4 = 0

x = \frac{1 + 17}{6}, x = \frac{1 - 17}{6}

Decimal Notation

x = 0.85385 \dots, x = - 0.52051 \dots

Solution steps

9 x^{2} - 3 x - 4 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- ( - 3 ) \pm ( - 3 ) ^{2} - 4 \cdot 9 ( - 4 )}{2 \cdot 9}

(- 3)^{2} - 4 \cdot 9 (- 4) = 317

x_{1, 2} = \frac{- ( - 3 ) \pm 3 17}{2 \cdot 9}

Separate the solutions

x_{1} = \frac{- ( - 3 ) + 3 17}{2 \cdot 9}, x_{2} = \frac{- ( - 3 ) - 3 17}{2 \cdot 9}

x = \frac{- ( - 3 ) + 3 17}{2 \cdot 9} : \frac{1 + 17}{6}

x = \frac{- ( - 3 ) - 3 17}{2 \cdot 9} : \frac{1 - 17}{6}

The solutions to the quadratic equation are:

x = \frac{1 + 17}{6}, x = \frac{1 - 17}{6}

90 = 66 e^{- 0.0174 (90)} + 75

x^{2} + 11 x + 28 < 0

50 - 98 x^{2}

5 x^{2} - 13 x = 6

What are the solutions to the equation 9x^2-3x-4=0 ?
The solutions to the equation 9x^2-3x-4=0 are x=(1+sqrt(17))/6 ,x=(1-sqrt(17))/6
Find the zeros of 9x^2-3x-4=0
The zeros of 9x^2-3x-4=0 are x=(1+sqrt(17))/6 ,x=(1-sqrt(17))/6