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人気のある代数 >

3y+7=5,x^7x-3y=1

解

3 y + 7 = 5, x^{7} x - 3 y = 1

解

x = \frac{1}{2 ^{\frac{3}{4}} 2 - 1} + \frac{2 - 1}{4 2 ^{3}} i, x = - \frac{1}{2 ^{\frac{3}{4}} 2 - 1} - \frac{2 - 1}{4 2 ^{3}} i, x = - \frac{1}{2 ^{\frac{3}{4}} 1 + 2} + \frac{1 + 2}{4 2 ^{3}} i, x = \frac{1}{2 ^{\frac{3}{4}} 1 + 2} - \frac{1 + 2}{4 2 ^{3}} i, x = \frac{1}{2 ^{\frac{3}{4}} 1 + 2} + \frac{1 + 2}{4 2 ^{3}} i, x = - \frac{1}{2 ^{\frac{3}{4}} 1 + 2} - \frac{1 + 2}{4 2 ^{3}} i, x = - \frac{1}{2 ^{\frac{3}{4}} 2 - 1} + \frac{2 - 1}{4 2 ^{3}} i, x = \frac{1}{2 ^{\frac{3}{4}} 2 - 1} - \frac{2 - 1}{4 2 ^{3}} i, y = - \frac{2}{3} y = - \frac{2}{3} y = - \frac{2}{3} y = - \frac{2}{3} y = - \frac{2}{3} y = - \frac{2}{3} y = - \frac{2}{3} y = - \frac{2}{3}

解答ステップ

[3 y + 7 = 5 x^{7} x - 3 y = 1]

解く

3 y + 7 = 5 : y = - \frac{2}{3}

y = - \frac{2}{3}

の解を以下に当てはめる:

x^{7} x - 3 y = 1

x^{7} x - 3 y = 1

では,

y

を

- \frac{2}{3}

に置き換える:

x = \frac{1}{2 ^{\frac{3}{4}} 2 - 1} + \frac{2 - 1}{4 2 ^{3}} i, x = - \frac{1}{2 ^{\frac{3}{4}} 2 - 1} - \frac{2 - 1}{4 2 ^{3}} i, x = - \frac{1}{2 ^{\frac{3}{4}} 1 + 2} + \frac{1 + 2}{4 2 ^{3}} i, x = \frac{1}{2 ^{\frac{3}{4}} 1 + 2} - \frac{1 + 2}{4 2 ^{3}} i, x = \frac{1}{2 ^{\frac{3}{4}} 1 + 2} + \frac{1 + 2}{4 2 ^{3}} i, x = - \frac{1}{2 ^{\frac{3}{4}} 1 + 2} - \frac{1 + 2}{4 2 ^{3}} i, x = - \frac{1}{2 ^{\frac{3}{4}} 2 - 1} + \frac{2 - 1}{4 2 ^{3}} i, x = \frac{1}{2 ^{\frac{3}{4}} 2 - 1} - \frac{2 - 1}{4 2 ^{3}} i

元のequationに当てはめて解を検算する

ゆえに,

3 y + 7 = 5, x^{7} x - 3 y = 1

の最終的な解は

x = \frac{1}{2 ^{\frac{3}{4}} 2 - 1} + \frac{2 - 1}{4 2 ^{3}} i, x = - \frac{1}{2 ^{\frac{3}{4}} 2 - 1} - \frac{2 - 1}{4 2 ^{3}} i, x = - \frac{1}{2 ^{\frac{3}{4}} 1 + 2} + \frac{1 + 2}{4 2 ^{3}} i, x = \frac{1}{2 ^{\frac{3}{4}} 1 + 2} - \frac{1 + 2}{4 2 ^{3}} i, x = \frac{1}{2 ^{\frac{3}{4}} 1 + 2} + \frac{1 + 2}{4 2 ^{3}} i, x = - \frac{1}{2 ^{\frac{3}{4}} 1 + 2} - \frac{1 + 2}{4 2 ^{3}} i, x = - \frac{1}{2 ^{\frac{3}{4}} 2 - 1} + \frac{2 - 1}{4 2 ^{3}} i, x = \frac{1}{2 ^{\frac{3}{4}} 2 - 1} - \frac{2 - 1}{4 2 ^{3}} i, y = - \frac{2}{3} y = - \frac{2}{3} y = - \frac{2}{3} y = - \frac{2}{3} y = - \frac{2}{3} y = - \frac{2}{3} y = - \frac{2}{3} y = - \frac{2}{3}

グラフ

人気の例

\frac{3 x}{4} = 15

24 + 4 n = - (n + 6)

solvefor h,a=2pir^2+2pirh

so l v e f or h, a = 2 π r^{2} + 2 π r h

x(x-4)-2=x^2-4(x+3)

x (x - 4) - 2 = x^{2} - 4 (x + 3)

-1/6*x-1/2+21*(x+2)=(-6*(x-3))/7

- \frac{1}{6} \cdot x - \frac{1}{2} + 21 \cdot (x + 2) = \frac{- 6 \cdot ( x - 3 )}{7}