solvefor x,kx^2+8x+2k=0

Lösung

x, k x^{2} + 8 x + 2 k = 0

x = \frac{- 8 + 64 - 8 k ^{2}}{2 k}, x = \frac{- 8 - 64 - 8 k ^{2}}{2 k}; k \neq = 0

Schritte zur Lösung

k x^{2} + 8 x + 2 k = 0

Löse mit der quadratischen Formel

x_{1, 2} = \frac{- 8 \pm 8 ^{2} - 4 k \cdot 2 k}{2 k}

Vereinfache

8^{2} - 4 k \cdot 2 k : 64 - 8 k^{2}

x_{1, 2} = \frac{- 8 \pm 64 - 8 k ^{2}}{2 k}; k \neq = 0

Trenne die Lösungen

x_{1} = \frac{- 8 + 64 - 8 k ^{2}}{2 k}, x_{2} = \frac{- 8 - 64 - 8 k ^{2}}{2 k}

x = \frac{- 8 + 64 - 8 k ^{2}}{2 k}; k \neq = 0

x = \frac{- 8 - 64 - 8 k ^{2}}{2 k}; k \neq = 0

Die Lösungen für die quadratische Gleichung sind:

x = \frac{- 8 + 64 - 8 k ^{2}}{2 k}, x = \frac{- 8 - 64 - 8 k ^{2}}{2 k}; k \neq = 0

so l v e f or x, x^{2} - 4 x y - 2 y^{2} - 3 = 0

2 (x + 4) = - (2 x - 3)^{2}

5 s^{2} + 8 s - 8 = 0

so l v e f or r, r^{2} = θ

36 = - 4 x^{2} - 50