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受欢迎的代数 >

solvefor A,C^2+2XB=AXB-A^2

解答

求解

A, C^{2} + 2 XB = A XB - A^{2}

解答

A = - \frac{- XB + X ^{2} B ^{2} + 4 ( - 2 XB - C ^{2} )}{2}, A = - \frac{- XB - X ^{2} B ^{2} + 4 ( - 2 XB - C ^{2} )}{2}

求解步骤

C^{2} + 2 XB = A XB - A^{2}

交换两边

A XB - A^{2} = C^{2} + 2 XB

将

2 XB

para o lado esquerdo

A XB - A^{2} - 2 XB = C^{2}

将

C^{2}

para o lado esquerdo

A XB - A^{2} - 2 XB - C^{2} = 0

改写成标准形式

a x^{2} + b x + c = 0

- A^{2} + XB A - 2 XB - C^{2} = 0

使用求根公式求解

A_{1, 2} = \frac{- XB \pm ( XB ) ^{2} - 4 ( - 1 ) ( - 2 XB - C ^{2} )}{2 ( - 1 )}

化简

(XB)^{2} - 4 (- 1) (- 2 XB - C^{2}) : X^{2} B^{2} + 4 (- 2 XB - C^{2})

A_{1, 2} = \frac{- XB \pm X ^{2} B ^{2} + 4 ( - 2 XB - C ^{2} )}{2 ( - 1 )}

将解分隔开

A_{1} = \frac{- XB + X ^{2} B ^{2} + 4 ( - 2 XB - C ^{2} )}{2 ( - 1 )}, A_{2} = \frac{- XB - X ^{2} B ^{2} + 4 ( - 2 XB - C ^{2} )}{2 ( - 1 )}

A = \frac{- XB + X ^{2} B ^{2} + 4 ( - 2 XB - C ^{2} )}{2 ( - 1 )} : - \frac{- XB + X ^{2} B ^{2} + 4 ( - 2 XB - C ^{2} )}{2}

A = \frac{- XB - X ^{2} B ^{2} + 4 ( - 2 XB - C ^{2} )}{2 ( - 1 )} : - \frac{- XB - X ^{2} B ^{2} + 4 ( - 2 XB - C ^{2} )}{2}

二次方程组的解是:

A = - \frac{- XB + X ^{2} B ^{2} + 4 ( - 2 XB - C ^{2} )}{2}, A = - \frac{- XB - X ^{2} B ^{2} + 4 ( - 2 XB - C ^{2} )}{2}

作图

流行的例子

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