x(3)^2+3x^2-3+3^2=0

解

x (3)^{2} + 3 x^{2} - 3 + 3^{2} = 0

x = - 1, x = - 2

解答ステップ

x (3)^{2} + 3 x^{2} - 3 + 3^{2} = 0

拡張

x \cdot 3^{2} + 3 x^{2} - 3 + 3^{2} : 3 x^{2} + 9 x + 6

3 x^{2} + 9 x + 6 = 0

解くとthe二次式

x_{1, 2} = \frac{- 9 \pm 9 ^{2} - 4 \cdot 3 \cdot 6}{2 \cdot 3}

9^{2} - 4 \cdot 3 \cdot 6 = 3

x_{1, 2} = \frac{- 9 \pm 3}{2 \cdot 3}

解を分離する

x_{1} = \frac{- 9 + 3}{2 \cdot 3}, x_{2} = \frac{- 9 - 3}{2 \cdot 3}

x = \frac{- 9 + 3}{2 \cdot 3} : - 1

x = \frac{- 9 - 3}{2 \cdot 3} : - 2

二次equationの解:

x = - 1, x = - 2