solvefor x,2x^2+12x+4=0

解

x, 2 x^{2} + 12 x + 4 = 0

x = - 3 + 7, x = - 3 - 7

十進法表記

x = - 0.35424 \dots, x = - 5.64575 \dots

解答ステップ

2 x^{2} + 12 x + 4 = 0

解くとthe二次式

x_{1, 2} = \frac{- 12 \pm 1 2 ^{2} - 4 \cdot 2 \cdot 4}{2 \cdot 2}

1 2^{2} - 4 \cdot 2 \cdot 4 = 47

x_{1, 2} = \frac{- 12 \pm 4 7}{2 \cdot 2}

解を分離する

x_{1} = \frac{- 12 + 4 7}{2 \cdot 2}, x_{2} = \frac{- 12 - 4 7}{2 \cdot 2}

x = \frac{- 12 + 4 7}{2 \cdot 2} : - 3 + 7

x = \frac{- 12 - 4 7}{2 \cdot 2} : - 3 - 7

二次equationの解:

x = - 3 + 7, x = - 3 - 7